@spotify95 @pinkteddyx64 @coleslaw

The Guinness World Records calculates average speed wrong:

It should be total distance traveled divided by total time taken. They calculate (first speed + second speed)/2

This is wrong Guinness World Records. Get it together

## GWR

- pinkteddyx64
- Co-founder
**Posts:**257106**Joined:**12 Feb 2014, 22:09**Reputation:**447**Location:**Scunthorpe**Gender:**

### Re: GWR

Kyx wrote:@spotify95 @pinkteddyx64 @coleslaw

The Guinness World Records calculates average speed wrong:

It should be total distance traveled divided by total time taken. They calculate (first speed + second speed)/2

This is wrong Guinness World Records. Get it together

**eriously, life's too short to be worried about retards on an internet forum.**

### Re: GWR

@pinkteddyx64 @spotify95 @coleslaw

Imagine that a car travels 1 mile in 12 seconds on the first go. On the second go the engine breaks so they have to push the car. This takes 3 hours.

For GWR the average speed would be (300 mph + 0.3 mph)/2 = 150 mph

The actual average speed is 2 miles/3 hours = 0.67 mph

Huge difference

Imagine that a car travels 1 mile in 12 seconds on the first go. On the second go the engine breaks so they have to push the car. This takes 3 hours.

For GWR the average speed would be (300 mph + 0.3 mph)/2 = 150 mph

The actual average speed is 2 miles/3 hours = 0.67 mph

Huge difference

My website can be found here: http://quantumquasar.forumotion.com/

- spotify95
- Founder and the king of TBAAJ
**Posts:**5326**Joined:**22 Nov 2015, 14:24**Reputation:**167**Gender:**

### Re: GWR

Kyx wrote:@pinkteddyx64 @spotify95 @coleslaw

Imagine that a car travels 1 mile in 12 seconds on the first go. On the second go the engine breaks so they have to push the car. This takes 3 hours.

For GWR the average speed would be (300 mph + 0.3 mph)/2 = 150 mph

The actual average speed is 2 miles/3 hours = 0.67 mph

Huge difference

Indeed, I always knew that speed = distance / time, the first one (u+v)/2 would only be relevant if an item starts at one speed and finishes at another speed (going back to Physics SUVAT equations)and completes the whole run like that.

So if a car started at rest and was at 60mph after traveling 0.5 miles (constant acceleration ofc) then you'd use s=[(v+u)/2]*t, with the bit in square brackets being how you calculate the speed.

If a car is traveling at a constant 60mph then use speed = dist / time. The same goes for if it has to be pushed. Therefore, as you stated, if it takes 3 hours and 12 seconds (combined time) to complete a total distance of 2 miles (both runs) then the average speed cannot possibly be 150mph, or anywhere near that...

Hope I've not completely fucked up somewhere in my calculations! (Feel free to correct me if I have.)

### Re: GWR

spotify95 wrote:Kyx wrote:@pinkteddyx64 @spotify95 @coleslaw

Imagine that a car travels 1 mile in 12 seconds on the first go. On the second go the engine breaks so they have to push the car. This takes 3 hours.

For GWR the average speed would be (300 mph + 0.3 mph)/2 = 150 mph

The actual average speed is 2 miles/3 hours = 0.67 mph

Huge difference

Indeed, I always knew that speed = distance / time, the first one (u+v)/2 would only be relevant if an item starts at one speed and finishes at another speed (going back to Physics SUVAT equations)and completes the whole run like that.

So if a car started at rest and was at 60mph after traveling 0.5 miles (constant acceleration ofc) then you'd use s=[(v+u)/2]*t, with the bit in square brackets being how you calculate the speed.

If a car is traveling at a constant 60mph then use speed = dist / time. The same goes for if it has to be pushed. Therefore, as you stated, if it takes 3 hours and 12 seconds (combined time) to complete a total distance of 2 miles (both runs) then the average speed cannot possibly be 150mph, or anywhere near that...

Hope I've not completely fucked up somewhere in my calculations! (Feel free to correct me if I have.)

My website can be found here: http://quantumquasar.forumotion.com/

Return to “General Discussion”

### Who is online

Users browsing this forum: No registered users and 1 guest